How to Know Which Newman Projection Is Most Stable

A Newman Projection focuses on one specific bond of the molecule and note which atoms are attached to these carbon atoms. The figure below shows as an example a Newman projection looking down the C 2-C 3 bond of octane.

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DO NOT FORGET TO SUBSCRIBEThis video shows step by step how to draw the most stable confirmation of any molecules.

. 2-3 means looking down the carbon 2 and carbon 3 bond. Begingroup A side note. 4 Rotate the rear groups on the C_2-C_3 bond 120 counterclockwise from the Newman projection shown and youll have it.

Is it possible for a company to have a sustainable competitive advantage Shea Gould a prominent New York law firm of 230 attorneys. The most stable one would have the rear hydrogen in between the front methyl and bromine in a staggered conformation to minimize lone-pair-bonding-electron repulsions. Correct option is A Anti staggered conformation is more stable than gauche and eclipsed conformations.

4 Rotate the rear groups on the C2C3 bond 120 counterclockwise from the Newman projection shown and youll have it. It is the most stable. -Therefore option A is most stable because the bulky groups bromine lie opposite to each other and form anti-staggered conformation.

Therefore the two largest substituents on each carbon of the Newman projection are as far apart from one another as possible leading to the least possible. You wont know what it is that you need to work on. 495 1903 Views.

Large groups which are anti to each other have the least energy possible and hence are more stable. For the question in title you could just move on with the Newman projections to determine the relative stabilities of various conformers. In this form the largest substituent coming off the front carbon is exactly 180 o degrees away from the largest substituent on the back carbon.

Lets say we have a molecule where in the Newman projection the front carbon has a hydrogen methyl and an ethyl and in the back carbon theres a hydrogen something like a S Cl or Br bigger than carbon but only one atom and something like another ethyl or isopropyl. As in anti conformation the bulky groups are oppositely placed at an angle of 180 0 thereby reducing the steric hindrance between the groups resulting in the stability of the molecule. Draw Newman projections of the lowest and highest energy conformations of propane.

Hence the correct option is A. Determine which two carbon atoms are being studied. The most stable form of the Newman projection is the anti conformation.

Add an eye with an arrow looking down the carbon-carbon bond being studied. I dont see why you want to convert the Newman structures to 3d bond line structures for the question and. Use a Newman projection to draw the most stable conformation of 3-methylpentane looking down the C2-C3 bond.

Draw a Newman projection looking down the C 2-C 3 bond of 1-butene in the conformation shown below C 2 should be your front carbon. Here the compound in option A is in anti staggered form. 44 Votes The most stable one would have the rear hydrogen in between the front methyl and bromine in a staggered conformation to minimize lone-pair- bonding-electron repulsions.

Notice that any staggered conformation is more stable than the most stable eclipsed conformation and gauche conformations are less stable than the anti conformations. A Newman projection is a representation of the molecule looking through a C-C single bond. While in B and D they are close to each other causing repulsion and less stability.

Option C is eclipsed so definitely high in energy and less stable than rest three conformers.

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